# Javascript sort string by last two digit

I have order id with combination of string and alpha characters like “30000-T04”, “30000-T10”, “30000-T05”, “30000-T01”, I want to sort this in ascending order. So let’s see how to do that.

To sort an array of strings by the last two digits, you can use the `sort()` method with a custom comparison function that extracts the last two digits of each string and compares them numerically.

Here’s an example code snippet that demonstrates this:

```<code class="">const arr = ["30000-T04", "30000-T10", "30000-T05", "30000-T01"];

arr.sort((a, b) => {
const bDigits = parseInt(b.slice(-2));
});

console.log(arr); // ["30000-T01", "30000-T04", "30000-T05", "30000-T10"]</code>```

In this example, the `sort()` method is called on the `arr` array, with a comparison function that takes two arguments (`a` and `b`) representing the elements being compared.

Inside the comparison function, the `slice()` method is used to extract the last two digits of each string, and the `parseInt()` function is used to convert them to numbers.

Finally, the function returns the result of subtracting `bDigits` from `aDigits`. This means that if `a` has a higher two-digit number than `b`, it will be placed before it in the sorted array.

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